Theo giả thiết, ta có:
a 2 + b 2 + c 2 = ab + bc + ac
2(a 2 + b 2 + c 2 ) = 2(ab + bc + ac)
2a 2 + 2b 2 + 2c 2 = 2ab + 2bc + 2ac
2a 2 + 2b 2 + 2c 2 - 2ab - 2bc - 2ac = 0
a 2 -2ab + b 2 + a 2 - 2ac + c 2 + b 2 - 2bc + c 2 = 0
(a - b) 2 + (a - c) 2 + (b - c) 2 = 0