Câu hỏi

Thực hiện các phép tính x 3 + 3 x 2 − 10 x x 3 + 6 x 2 − 25 − 2 x − x 2 x + 5

Thực hiện các phép tính

$\frac{x ^{3} + 6 x ^{2} - 25}{x ^{3} + 3 x ^{2} - 10 x} - \frac{x + 5}{2 x - x ^{2}}$

H. Hoàng

Giáo viên

Xác nhận câu trả lời

Giải thích

= = = = = = x 3 + 3 x 2 − 10 x x 3 + 6 x 2 − 25 − 2 x − x 2 x + 5 x ( x 2 + 3 x − 10 ) x 3 + 6 x 2 − 25 − x ( 2 − x ) x + 5 x ( x − 2 ) ( x + 5 ) x 3 + 6 x 2 − 25 + x ( x − 2 ) x + 5 x ( x − 2 ) ( x + 5 ) x 3 + 6 x 2 − 25 + ( x + 5 ) 2 x ( x − 2 ) ( x + 5 ) x 3 + 6 x 2 − 25 + x 2 + 10 x + 25 x ( x − 2 ) ( x + 5 ) x 3 + 7 x 2 + 10 x x ( x − 2 ) ( x + 5 ) x ( x + 2 ) ( x + 5 ) = x + 2

$= = = = = = \frac{x ^{3} + 6 x ^{2} - 25}{x ^{3} + 3 x ^{2} - 10 x} - \frac{x + 5}{2 x - x ^{2}} \frac{x ^{3} + 6 x ^{2} - 25}{x ( x ^{2} + 3 x - 10 )} - \frac{x + 5}{x ( 2 - x )} \frac{x ^{3} + 6 x ^{2} - 25}{x ( x - 2 ) ( x + 5 )} + \frac{x + 5}{x ( x - 2 )} \frac{x ^{3} + 6 x ^{2} - 25 + ( x + 5 ) ^{2}}{x ( x - 2 ) ( x + 5 )} \frac{x ^{3} + 6 x ^{2} - 25 + x ^{2} + 10 x + 25}{x ( x - 2 ) ( x + 5 )} \frac{x ^{3} + 7 x ^{2} + 10 x}{x ( x - 2 ) ( x + 5 )} \frac{x ( x + 2 ) ( x + 5 )}{x ( x - 2 ) ( x + 5 )} = x + 2$