Đặt t = sin x thì d t = cos x d x
f ( x ) = ∫ y ′ d x = ∫ sin 7 x ( 1 − sin 2 x ) cos x d x = ∫ t 7 ( 1 − t 2 ) d t = ∫ ( t 7 − t 9 ) d t = 8 t 8 − 10 t 10 + C = 8 s i n 8 x − 10 s i n 10 x + C V ı ˋ f ( π ) = 79 n e ˆ n C = 79. Vậy f ( x ) = 8 s i n 8 x − 10 s i n 10 x + 79.