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Cho a > 1. Mệnh đề nào sau đây là đúng ?

Cho  Mệnh đề nào sau đây là đúng ?

  1. a to the power of negative square root of 3 end exponent greater than 1 over a to the power of square root of 5 end exponent

E. Elsa

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Giải thích

Chọn C. Xét đáp án A có a 3 a 2 ​ ​ = a 3 − 1 ​ = 3 a ​ 1 ​ < 1 , ∀ a > 1 nên loại. Xét đáp án Bcó a ​ = a 2 1 ​ > a 3 1 ​ , ∀ a > 1 nên loại. Xét đáp án Ccó mà 1" data-mathml="«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»0«/mn»«mo»§#60;«/mo»«msup»«mi»a«/mi»«msqrt»«mn»3«/mn»«/msqrt»«/msup»«mo»§#60;«/mo»«msup»«mi»a«/mi»«msqrt»«mn»5«/mn»«/msqrt»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«mo»§#8704;«/mo»«mi»a«/mi»«mo»§#62;«/mo»«mn»1«/mn»«/math»" role="math" src="data:image/png;base64,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" style="max-width: none;">do \frac1{a^\sqrt5}" data-mathml="«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mn»3«/mn»«/msqrt»«mo»§#60;«/mo»«msqrt»«mn»5«/mn»«/msqrt»«mo»§#8658;«/mo»«mfrac»«mn»1«/mn»«msup»«mi»a«/mi»«msqrt»«mn»3«/mn»«/msqrt»«/msup»«/mfrac»«mo»§#62;«/mo»«mfrac»«mn»1«/mn»«msup»«mi»a«/mi»«msqrt»«mn»5«/mn»«/msqrt»«/msup»«/mfrac»«/math»" role="math" src="data:image/png;base64,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" style="max-width: none;"> Nên chọn C. Xét đáp án Dcó a 2016 < a 2017 , ∀ a > 1 ⇒ a 2016 1 ​ > a 2017 1 ​ nên loại.

Chọn C.

Xét đáp án A có  nên loại.

Xét đáp án B có  nên loại.

Xét đáp án C có a to the power of negative square root of 3 end exponent equals 1 over a to the power of square root of 3 end exponent mà 0 less than a to the power of square root of 3 end exponent less than a to the power of square root of 5 end exponent comma space for all a greater than 1 do square root of 3 less than square root of 5 rightwards double arrow 1 over a to the power of square root of 3 end exponent greater than 1 over a to the power of square root of 5 end exponent

Nên chọn C.

Xét đáp án D có   nên loại.

1

Câu hỏi tương tự

Cho hàm số y = x − 2 x + 3 ​ . Mệnh đề nào sau đây đúng?

0

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