a,
Gọi số mol nAl=a, nZn=b
==>27a+65b=9.2. (1)
2Al+6HCl ----->2AlCl3+3H2
a------3a-------------------------3a/2
Zn+2HCl--->ZnCl2+H2
b-----2b--------------------b
===>3a/2+b=5.6 : 22.4=0.25. (2)
===>a=0.1 và b=0.1
===>mAl=2.7(g) ==>%mAl=29.34%
===>%mZn= 70.66%
b,
nHCl=0.3+0.2=0.5 (mol)
V-HCl=11.2(lít)