4x^2 - 2x -10x +5 = 0
x^2 + x - 12 = 0
x^2 - 3x^2 ...

Question

4x^2 - 2x -10x +5 = 0
x^2 + x - 12 = 0
x^2 - 3x^2 + 3x - 1 + 2(x^2 - x) = 0

Ngọc N · Answer

4x^2-2x-10+5=0
(=) (4x^2-2x)+(-10x+5)=0
(=) 2x(2x-1)-5(2x-1)=0
(=) (2x-5)(2x-1)=0
(=)2x-5 =0 hoặc 2x-1=0
(=) 2x=5 hoặc 2x=1
(=) x=5/2 hoặc x=1/2
   Vậy.......

Ngọc N · Answer

x^2+x-12=0
(=)x^2-3x+4x-12=0
(=)x(x-3)+4(x-3)=0
(=)(x+4)(x-3)=0
(=) x+4=0 hoặc x-3=0
(=) x=-4 hoặc x=3
 Vậy.........

Ngọc N · Answer

x^2-3x^2+3x-1+2(x^2-x)=0
(=) -2x^2+3x-1+2x(x-1)=0
(=)(-2x^2+2x+x-1)+2x(x-1)=0
(=)[-2x(x-1)+(x-1)]+2x(x-1)=0
(=) (-2x+1)(x-1)+2x(x-1)=0
(=)(x-1)(-2x+1+2x)=0
(=)(x-1).1=0
(=)  x-1=0
(=). x=1
   Vậy......

4x^2 - 2x -10x +5 = 0 x^2 + x - 12 = 0 x^2 - 3x^2 + 3x - 1 + 2(x^2 - x) = 0

4x^2-2x-10+5=0 (=) (4x^2-2x)+(-10x+5)=0 (=) 2x(2x-1)-5(2x-1)=0 (=) (2x-5)(2x-1)=0 (=)2x-5 =0 hoặc 2x-1=0 (=) 2x=5 hoặc 2x=1 (=) x=5/2 hoặc x=1/2 Vậy.......

x^2+x-12=0 (=)x^2-3x+4x-12=0 (=)x(x-3)+4(x-3)=0 (=)(x+4)(x-3)=0 (=) x+4=0 hoặc x-3=0 (=) x=-4 hoặc x=3 Vậy.........

x^2-3x^2+3x-1+2(x^2-x)=0 (=) -2x^2+3x-1+2x(x-1)=0 (=)(-2x^2+2x+x-1)+2x(x-1)=0 (=)[-2x(x-1)+(x-1)]+2x(x-1)=0 (=) (-2x+1)(x-1)+2x(x-1)=0 (=)(x-1)(-2x+1+2x)=0 (=)(x-1).1=0 (=) x-1=0 (=). x=1 Vậy......

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